## SAT Subject Test Chemistry

__PART 2__

__REVIEW OF MAJOR TOPICS__

__CHAPTER 6__

__CHAPTER 6__

__Stoichiometry (Chemical Calculations) and the Mole Concept__

__Stoichiometry (Chemical Calculations) and the Mole Concept__

__DENSITY AND MOLAR MASS__

__DENSITY AND MOLAR MASS__

Since the density of a gas is usually given in grams/liter of gas at STP, we can use the molar volume to molar mass relationship to solve the following types of problems.

**EXAMPLE 1: **Find the molar mass of a gas when the density is given as 1.25grams/liter.

Because it is known that 1 mole of a gas occupies 22.4 liters at STP, we can solve this problem by multiplying the mass of 1 liter by 22.4 liters/mole.

Even if the weight given is not for 1 liter, the same setup can be used.

**TIP **

**REMEMBER **For a dry gas at STP, the mass of 1 liter × 22.4 = the molar mass of the gas.

**EXAMPLE 2: **If 3.00 liters of a gas weighs 2.00 grams, find the molar mass.

Solution:

You can also find the density of a gas if you know the molar mass. Since the molar mass occupies 22.4 liters at STP, dividing the molar mass by 22.4 liters will give you the mass per liter, or the density.

**EXAMPLE 3: **Find the density of oxygen at STP.

Solution:

Oxygen is diatomic in its molecular structure.

O_{2 }= molar mass of 2 × 16.0 or 32.0 g/mol 32.0 g/mol occupies 22.4 L.

Therefore

You can find the density of a gas, then, by dividing its molar mass by 22.4 liters.

**TIP **

For a dry gas at STP,