Definite Integrals - Review the Knowledge You Need to Score High - 5 Steps to a 5 AP Calculus AB & BC

5 Steps to a 5 AP Calculus AB & BC, 2012-2013 Edition (2011)

STEP 4. Review the Knowledge You Need to Score High

Chapter 11. Definite Integrals

IN THIS CHAPTER

Summary: In this chapter, you will be introduced to the summation notation, the concept of a Riemann Sum, the Fundamental Theorems of Calculus, and the properties of definite integrals. You will also be shown techniques for evaluating definite integrals involving algebraic, trigonometric, logarithmic, and exponential functions. In addition, you will learn how to work with improper integrals. The ability to evaluate integrals is a prerequisite to doing well on the AP Calculus exams.

Image

Key Ideas

Image Summation Notation

Image Riemann Sums

Image Properties of Definite Integrals

Image The First Fundamental Theorem of Calculus

Image The Second Fundamental Theorem of Calculus

Image Evaluating Definite Integrals

Image Improper Integrals

11.1 Riemann Sums and Definite Integrals

Main Concepts:

Sigma Notation, Definition of a Riemann Sum, Definition of a Definite Integral, and Properties of Definite Integrals

Sigma Notation or Summation Notation

Image

where i is the index of summation, l is the lower limit and n is the upper limit of summation. (Note: The lower limit may be any non-negative integer ≤ n.)

Examples

Image

Summation Formulas

If n is a positive integer, then:

1. Image

2. Image

3. Image

4. Image

5. Image

Example

Evaluate Image.

Rewrite:

Image

(Note: This question has not appeared in an AP Calculus AB Exam in recent years).

Image

• Remember: In exponential growth/decay problems, the formulas are Image and y = y0ekt.

Definition of a Riemann Sum

Let f be defined on [a, b] and xi be points on [a, b] such that x0 = a, xn = b, and a < x1 < x2 < x3 … < xn−1 < b. The points a, x1, x2, x3, … xn+1, and b form a partition of f denoted as Δ on [a, b]. Let Δxi be the length of the ith interval [xi−1, xi] and ci be any point in the ith interval. Then the Riemann sum of f for the partition is Image.

Example 1

Let f be a continuous function defined on [0, 12] as shown below.

Image

Find the Riemann sum for f(x) over [0, 12] with 3 subdivisions of equal length and the midpoints of the intervals as ci.

Length of an interval Image. (See Figure 11.1-1.)

Image

Figure 11.1-1

Image

The Riemann sum is 596.

Example 2

Find the Riemann sum for f(x) = x3 + 1 over the interval [0, 4] using 4 subdivisions of equal length and the midpoints of the intervals as ci. (See Figure 11.1-2.)

Image

Figure 11.1-2

Length of an interval Image; ci = 0.5 + (i − 1) = i − 0.5.

Image

Enter Σ ((1 − 0.5)3 + 1, i, 1, 4) = 66.

The Riemann sum is 66.

Definition of a Definite Integral

Let f be defined on [a, b] with the Riemann sum for f over [a, b] written as Image. If max Δxi is the length of the largest subinterval in the partition and the Image exists, then the limit is denoted by:

Image

Image is the definite integral of f from a to b.

Example 1

Use a midpoint Riemann sum with three subdivisions of equal length to find the approximate value of Image.

Image

midpoints are x = 1, 3, and 5.

Image

Example 2

Using the limit of the Riemann sum, find Image.

Using n subintervals of equal lengths, the length of an interval

Image

Let ci = xi; max Δxi → 0 ⇒ n → ∞.

Image

Thus, Image.

(Note: This question has not appeared in an AP Calculus AB Exam in recent years.)

Properties of Definite Integrals

1. If f is defined on [a, b], and the limit Image exists, then f is integrable on [a, b].

2. If f is continuous on [a, b], then f is integrable on [a, b].

If f (x), g (x), and h(x) are integrable on [a, b], then

3. Image

4. Image

5. Image when C is a constant.

6. Image

7. Image provided f(x) ≥ 0 on [a, b].

8. Image provided f(x) ≥ g(x) on [a, b].

9. Image

10. Image; provided g(x) ≤ f(x) ≤ h(x) on [a, b].

11. Image; provided mf(x) ≤ M on [a, b].

12. Image; provided f(x) is integrable on an interval containing a, b, c.

Examples

1. Image

2. Image

3. Image

4. Image

5. Image

Note: Or Image

Image a, b, c do not have to be arranged from smallest to largest.

The remaining properties are best illustrated in terms of the area under the curve of the function as discussed in the next section.

Image

• Do not forget that Image.

11.2 Fundamental Theorems of Calculus

Main Concepts:

First Fundamental Theorem of Calculus, Second Fundamental Theorem of Calculus

First Fundamental Theorem of Calculus

If f is continuous on [a, b] and F is an antiderivative of f on [a, b], then

Image

Note: F(b) − F(a) is often denoted as Image.

Example 1

Evaluate Image.

Image

Example 2

Evaluate Image.

Image

Example 3

If Image, k > 0, find k.

Image

Image

Example 4

If f′(x) = g(x), and g is a continuous function for all real values of x, express Image in terms of f.

Let u = 3x; du = 3dx or Image.

Image

Example 5

Evaluate Image.

Cannot evaluate using the First Fundamental Theorem of Calculus since Image is discontinuous at x = 1.

Example 6

Using a graphing calculator, evaluate Image.

Using a TI-89 graphing calculator, enter Image and obtain 2π.

Second Fundamental Theorem of Calculus

If f is continuous on [a, b] and Image, then F′(x) = f(x) at every point x in [a, b].

Example 1

Evaluate Image.

Let u = 2t; du = 2dt or Image.

Image

Example 2

If Image find h′(8).

Image

Example 3

Find Image; if Image.

Let u = 2x; then Image.

Rewrite: Image.

Image

Example 4

Find Image; if Image.

Rewrite: Image.

Let u = x2; then Image.

Rewrite: Image.

Image

Example 5

Find Image if Image.

Image

Image

Example 6

Image, integrate to find F(x) and then differentiate to find f′(x).

Image

11.3 Evaluating Definite Integrals

Main Concepts:

Definite Integrals Involving Algebraic Functions; Definite Integrals Involving Absolute Value; Definite Integrals Involving Trigonometric, Logarithmic, and Exponential Functions; Definite Integrals Involving Odd and Even Functions

Image

• If the problem asks you to determine the concavity of f′(not f), you need to know if f″ is increasing or decreasing, or if f″′ is positive or negative.

Definite Integrals Involving Algebraic Functions

Example 1

Evaluate Image.

Rewrite:

Image

Verify your result with a calculator.

Example 2

Evaluate Image.

Begin by evaluating the indefinite integral Image.

Let u = x2 − 1; du = 2x dx or Image.

Rewrite: Image.

Thus the definite integral Image.

Verify your result with a calculator.

Example 3

Evaluate Image.

Image

Verify your result with a calculator.

Image

• You may bring up to 2 (but no more than 2) approved graphing calculators to the exam.

Definite Integrals Involving Absolute Value

Example 1

Evaluate Image.

Set 3x − 6 = 0; x = 2; thus Image.

Rewrite integral:

Image

Verify your result with a calculator.

Example 2

Evaluate Image.

Set x2 − 4 = 0; x = ± 2.

Thus Image.

Thus,

Image

Verify your result with a calculator.

Image

• You are not required to clear the memories in your calculator for the exam.

Definite Integrals Involving Trigonometric, Logarithmic, and Exponential Functions

Example 1

Evaluate Image.

Rewrite:

Image

Verify your result with a calculator.

Example 2

Evaluate Image.

Let u = 3t; du = 3dt or Image.

Rewrite the indefinite integral:

Image

Image

Verify your result with a calculator.

Example 3

Evaluate Image.

Let u = ln t, Image.

Rewrite:

Image

Verify your result with a calculator.

Example 4

Evaluate Image.

Let u = x2 + 1; du = 2x dx or Image.

Image

Rewrite: Image.

Verify your result with a calculator.

Definite Integrals Involving Odd and Even Functions

If f is an even function, that is, f (−x) = f(x), and is continuous on [−a, a], then

Image

If f is an odd function, that is, F(x) = − f(−x), and is continuous on [−a, a] then

Image

Example 1

Evaluate Image.

Since f(x) = cos x is an even function,

Image

Verify your result with a calculator.

Example 2

Evaluate Image.

Since f(x) = x4x2 is an even function, i.e., f(−x) = f(x), thus

Image

Verify your result with a calculator.

Example 3

Evaluate Image.

Since f(x) = sin x is an odd function, i.e., f(−x) = − f(x), thus

Image

Verify your result algebraically.

Image

You can also verify the result with a calculator.

Example 4

If Image for all values of k, then which of the following could be the graph of f ? (See Figure 11.3-1.)

Image

Figure 11.3-1

Image

Image, then Image.

Thus f is an even function. Choice (C).

11.4 Improper Integrals

Image

Main Concepts: Infinite Intervals of Integration, Infinite Discontinuities

Infinite Intervals of Integration

Improper integrals are integrals with infinite intervals of integration or infinite discontinuities within the interval of integration. For infinite intervals of integration, Image. If the limit exists, the integral converges. Image for some value c.

Example 1

Evaluate Image.

Image so the integral diverges.

Example 2

Evaluate Image.

Since both limits of integration are infinite, consider the sum of the improper integrals Image. This sum is the sum of the limits Image. Since the limit exists, the integral converges and Image.

Infinite Discontinuities

If the function has an infinite discontinuity at one of the limits of integration, then Image. If an infinite discontinuity occurs at x = c within the interval of integration (a, b), then the integral can be broken into sections at the discontinuity and the sum of the two improper integrals can be found. Image

Example

Evaluate Image.

Since Image has an infinite discontinuity at Image, the integral is improper.

Evaluate Image. Since the limit exists, Image.

11.5 Rapid Review

1. Evaluate Image.

Answer: Image.

2. Evaluate Image.

Answer: Image.

3. If Image, find G′(4).

Answer: G′(x) = (2x + 1)3/2 and G′(4) = 93/2 = 27.

4. If Image, find k.

Answer: Image.

5. If G(x) is a antiderivative of (ex + 1) and G(0) = 0, find G(1).

Answer: G(x) = ex + x + C

G(0) = e0 + 0 + C = 0 ⇒ C = −1.

G(1) = e1 + 1 − 1 = e.

6. If G′(x) = g(x), express Image.

Answer: Let u = 4x Image.

Image. Thus Image.

7. Image

Answer: Image.

8. Image

Answer: Image.

11.6 Practice Problems

Part A—The use of a calculator is not allowed.

Evaluate the following definite integrals.

1. Image

2. Image

3. Image

4. Image

5. If Image, find k.

6. Image

7. If f′(x) = g(x) and g is a continuous function for all real values of x, express Image in terms of f.

8. Image

9. Image

10. If Image, find Image.

11. Image

12. Image

Part B—Calculators are allowed.

13. Find k if Image

14. Evaluate Image to the nearest 100th.

15. If Image, find Image.

16. Use a midpoint Riemann sum with four subdivisions of equal length to find the approximate value of Image.

17. Given Image

and Image, find

Image

18. Evaluate Image.

19. Find Image.

20. Let f be a continuous function defined on [0, 30] with selected values as shown below:

Image

Use a midpoint Riemann sum with three subdivisions of equal length to find the approximate value of Image.

Image

21. Image

22. Image

23. Image

24. Image

25. Image

11.7 Cumulative Review Problems

(Calculator) indicates that calculators are permitted.

26. Evaluate Image.

27. Find Image at x = 3 if y = ln|x2 − 4|.

28. The graph of f′, the derivative of f, −6 ≤ x ≤ 8 is shown in Figure 11.7-1.

Image

Figure 11.7-1

(a) Find all values of x such that f attains a relative maximum or a relative minimum.

(b) Find all values of x such that f is concave upward.

(c) Find all values of x such that f has a change of concavity.

29. (Calculator) Given the equation 9x2 + 4y2 − 18x + 16y = 11, find the points on the graph where the equation has a vertical or horizontal tangent.

30. (Calculator) Two corridors, one 6 feet wide and another 10 feet wide meet at a corner. (See Figure 11.7-2.) What is the maximum length of a pipe of negligible thickness that can be carried horizontally around the corner?

Image

Figure 11.7-2

31. Evaluate Image.

32. Determine the speed of an object moving along the path described by x = 3 − 2t2, y = t2 + 1 when Image.

33. Image

11.8 Solutions to Practice Problems

Part A—The use of a calculator is not allowed.

1.

Image

2. Let u=x − 2 du = dx.

Image

Thus

Image

3. Let u = t + 1 du = dt and t = u − 1.

Rewrite:

Image

Image

= 2 − ln 2.

4. Set x − 3 = 0; x = 3.

Image

5. Image

Set 3k2k = 4 ⇒ 3k2k − 4 = 0

⇒ (3k − 4)(k + 1) = 0

Image or k = −1

Verify your results by evaluating

Image and Image.

6. Let u = 1 + cos x; du = −sin x dx or − du = sin x dx.

Image

7. Let u = 4x; du = 4 dx or Image.

Image

8.

Image

9. Let u = t + 3; du = dt.

Image

10. f′(x) = tan2 x;

Image

11. Let u = x2; du = 2x dx or Image.

Image

Note that f(x) = 4xImage is an odd function.

Thus, Image.

12.

Image

Note that f(x) = cosxx2 is an even function. Thus, you could have written Image and obtained the same result.

Part B—Calculators are allowed.

13.

Image

Set 4 + 2k = 10 and k = 3.

14. Enter Image, x, −1.2, 3.1) and obtain −4.70208 ≈ −4.702.

15.

Image

16. Image

Midpoints are x = 1, 3, 5, and 7.

Image

17.

Image

Image

18.

Image

19.

Image

20. Image

Midpoints are x = 5, 15, and 25.

Image

21.

Image

22.

Image

23.

Image

24.

Image

25.

Image

11.9 Solutions to Cumulative Review Problems

26.

Image

27.

Image

28. (a) (See Figure 11.9-1.)

Image

Figure 11.9-1

The function f has a relative minimum at x = −5 and x = 3, and f has a relative maximum at x = −1 and x = 7.

(b) (See Figure 11.9-2.)

Image

Figure 11.9-2

The function f is concave upward on intervals (−6, −3) and (1, 5).

(c) A change of concavity occurs at x = −3, x = 1, and x = 5.

29. (Calculator) Differentiate both sides of

Image

Horizontal tangent Image.

Image

Using a calculator, enter [Solve] (4y^2 + 16y − 20 =0, y); obtaining y = −5 or y = 1.

Thus at each of the points at (1, 1) and (1, −5) the graph has a horizontal tangent. Vertical tangent Image is undefined.

Set 8y + 16 = 0 ⇒ y = −2.

At y = −2, 9x2 + 16 − 18x − 32 = 11

⇒ 9x2 − 18x − 27 = 0.

Enter [Solve] (9x2 − 8x − 27 = 0, x) and obtain x = 3 or x = −1.

Thus, at each of the points (3, −2) and (−1, −2), the graph has a vertical tangent. (See Figure 11.9-3.)

Image

Figure 11.9-3

30. (Calculator)

Step 1. (See Figure 11.9-4.) Let P = x + y where P is the length of the pipe and x and y are as shown. The minimum value of P is the maximum length of the pipe to be able to turn in the corner. By similar triangles, Image and thus, Image

Image

Image

Figure 11.9-4

Step 2. Find the minimum value of P. Enter Image. Use the [Minimum] function of the calculator and obtain the minimum point (9.306, 22.388).

Step 3. Verify with the First Derivative Test.

Enter y 2 = (y1(x), x) and observe. (See Figure 11.9-5.)

Image

Figure 11.9-5

Step 4. Check endpoints. The domain of x is (6, ∞). Since x = 9.306 is the only relative extremum, it is the absolute minimum.

Thus the maximum length of the pipe is 22.388 feet.

31.

Image

32. Image. The speed of the object is Image. Evaluated at Image, the speed is Image.

33. Integrate Image by parts with u = 2x, du = 2dx, Image, and Image. Then Image. Simplifying this expression, we get Image.