Organic Chemistry: Concepts and Applications - Headley Allan D. 2020

Acid—Base Reactions in Organic Chemistry
7.3 Relative Strengths of Acids and Conjugate Bases

The degree to which acids dissociate in water (and other solvents) is different for each acid. Each acid dissociates based on the equilibrium established in a particular solvent. The magnitude of such an equilibrium constant (Keq) reflects the relative distribution of the dissociated species to the undissociated acid in solution. It is known that nitric acid cannot be ingested; on the other hand, acetic acid (in the form of vinegar in salad dressings) can be ingested! Nitric acid is a much stronger acid than acetic acid and, as a result, is a very dangerous corrosive acid. The relative strengths of acids are typically measured in water. Since water is a base, an acid—base chemical reaction takes place between the acid (HA) and water (the base) to form protonated water, H3O+, and A, which are also known as the conjugate acid and base, respectively, as shown in Reaction (7-3) for an acid HA.

(7-3)Image

At equilibrium, all the species, H3O+, A, HA, and H2O, exist in solution, and the concentrations of all the species are used to calculate the equilibrium constant for a particular acid, HA. The expression for the equilibrium constant is shown in Eq. (7-4), where Keq is the equilibrium constant and the concentrations for the various species are shown in square brackets.

(7-4)Image

Since water is the solvent making its concentration very high, compared to the other species in solution, its concentration can be considered to be a constant. Thus, the expression in Eq. (7-4) can be modified as shown in Eq. (7-5) and even further to Eq. (7-6) if [H2O]K made equal to a new constant, Ka, the acidity equilibrium constant in water as a solvent.

(7-5)Image

(7-6)Image

The Ka for HCl has been determined experimentally to be 1 × 107, and for acetic acid, the Ka is 1.75 × 10−5. Since 1 × 107 is a much larger number than 1.75 × 10−5, HCl is a stronger acid producing more protons (H+) in water, compared to acetic acid. Another way of stating this observation is that for an equal concentration of both HCl and acetic acid, the concentration of the protons in a solution of HCl is much greater than that of a solution of acetic acid.

Since these Ka values tend to be either very large or very small and very cumbersome to use, an easier method was devised to compress or expand these numbers, and at the same time convey the same meaning of the relative strengths of acids. The negative log of Ka or pKa values are routinely used to reflect the relative strength of acids, and the relationship between Ka and pKa is shown in Eq. (7-7).

(7-7)Image

Thus, the pKa for HCl is −7 and for acetic acid is 4.75.

Problem 7.2

i. Determine the pKa of the acids that have the following Ka values? Which of the acids with the given Ka values would be the weakest?

1. Ka = 1.3 × 10−5

2. Ka = 1.3 × 105

3. Ka = 1.3 × 10−10

4. Ka = 2.3 × 1025

5. Ka = 7.9 × 10−12

ii. Given the pKa values shown below, determine the Ka values? Which of the acids with the given pKa values would be the strongest?

1. pKa = 35

2. pKa = 12

3. pKa = 4.6

4. pKa = 24

5. pKa = −14

A pKa table gives the pKa values of common acids used in organic chemistry and the pKa values of some acids are shown in Table 7.1.

An acid with a pKa value that is more positive than the pKa value of another acid means that the acid with the more positive pKa value is the weaker acid. For example, if two acids have pKa values of 3.75 and 8.34, respectively, the acid with a pKa value of 3.75 is a stronger acid than the acid with a pKa value of 8.34. Also, notice that the pKa for some of these acids are outside the range of the acidity of water, this means that their pKa values are not measurable in water, but in other solvents. For example, NH3 is a weak acid, pKa = 38, but its conjugate base is extremely strong and will deprotonate water.

The pKa table is very helpful in predicting the acidity of compounds and equally important, it is also very helpful in predicting the relative strength of conjugate bases. Consider the two acids, HBr and HCN with the acidity in water is shown in Reactions (7-8) and (7-9).

Table 7.1 pKa for various acids of organic chemistry.

Acid

Conjugate base

pKa

HI

I

9.5

HBr

Br

9.0

HCl

Cl

7.0

H3O+

H2O

1.7

CH3COOH

CH3COO

4.8

H2S

SH

7.0

HCN

CN

9.2

NH4+

NH3

9.4

CH3SH

CH3S

10.0

R-CHCOR

Enolate

~19

CH3OH

CH3O

15.2

H2O

OH

15.7

CH3CH2CN

CH3CHCN

25

CH3C═CH (alkynes)

CH3C═C

25

H2

H

35

NH3

NH2

38

C6H6

C6H5

43

CH3CH═CH2

CH3CH═CH

44

CH4

CH3

50

CH3CH3

CH3CH2

50

(7-8)Image

(7-9)Image

It is known that the conjugate base of a strong acid is weak and as a result, a determination can be made whether a conjugate base of an acid is strong or weak based by just knowing the pKa value of an acid. Note that the conjugate bases shown in Reactions (7-8) and (7-9) are negatively charged. A stable negative charge has the ability to accommodate that charge. Thus, very electronegative or polarizable species will be better able to accommodate a charge, compared to less electronegative or polarizable species. For the reaction given in Reaction (7-8), the Br anion is a large atom and hence good at stabilizing the negative charge of the conjugate base. As a result, it is a weak base and its conjugate acid is a strong acid. On the other hand, the CN anion of Reaction (7-9) is not as polarizable as the bromide anion and is considered to be a harder base as described by the Pearson hard-soft base concept. As a result, the cyanide anion (CN) is a stronger conjugate base than the bromide anion, which makes the conjugate acid, HCN, a weaker acid than HBr. This conclusion that Br is a weak conjugate base and hence the conjugate acid, HBr is a strong acid is confirmed from the pKa values in the pKa table. Similarly, the conjugate base CN is a strong conjugate base, which makes its conjugate acid, HCN a weak acid. This concept will be utilized throughout this course to predict the relative strengths of conjugate bases and acids.

Problem 7.3

i. Give the structure of the conjugate base of each of the following acids.

1. H2O

2. CH3OH

3. HCN

4. CH3SH

5. H2S

ii. Utilize Table 7.1 to determine which of the following pairs of acids is stronger and give the structures of the conjugate bases of each acid.

1. CH3COOH and CH3OH

2. NH3 and CH3OH

3. CH4 and CH3OH