SAT SUBJECT TEST MATH LEVEL 2
PART 2
REVIEW OF MAJOR TOPICS
CHAPTER 2
Geometry and Measurement
2.2 Three-Dimensional Geometry
Answers and Explanations
Surface Area and Volume
1. (C) The volume of the cube is x3. The radius of the cylinder is 
, and its height is x . Substitute these into the formula for the volume of a cylinder:
2. (C) V = πr2h, and total area = 2πr2 + 2πrh . Setting these two equal yields rh = 2r + 2h . Therefore, 
. Since h must be positive, the smallest integer value of r is 3.
3. * (D) The length of the longest segment is 
Coordinates in Three Dimensions
1. (D) The square of the distance between P and Q is 9, so
(x – 3)2 + (–1 – (–3))2 + (–1 – 1)2 = 9, or (x – 3)2 = 1.
Therefore, x – 3 = ±1, so x = 2 or 4.
2. (D) Since the y -coordinate is zero, the point must lie in the xz plane.
3. * (C) The line 3x + 2y = 7 has x -intercept 
and y -intercept 
. The part of this line that lies in the first quadrant forms a triangle with the coordinate axes. Rotating this triangle about the x -axis produces a cone with radius and height . The volume of this cone is 
.